Consider the following route of reactions:
R2SiCl2 + Water (A) (B)
Compound(B) in above reaction is :

Question

Consider the following route of reactions:
R2SiCl2 + Water $ ightarrow$ (A) $\xrightarrow{ ext{Polymerisation}}$ (B)
Compound(B) in above reaction is :

Prashant Kotian · Accepted Answer

Correct answer: B. Step 1: Most lead salts are highly insoluble, but their solubilities can vary significantly depending on water temperature. Step 2: Lead(II) chloride (PbCl2) is sparingly soluble in cold water (Ksp is relatively low at room temperature). Step 3: However, its solubility increases substantially in hot water, making PbCl2 fairly soluble in hot water. Thus, option (b) is correct.

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