19,000+ solved questions for JEE Advanced, JEE Mains, NEET & IChO — with answers and expert explanations.
5 mL of N-HCl, 20 mL of N/2 H₂SO₄ milli equivalent and 30 mL of N/3 HNO₃ are mixed together and the volume is made to 1L. The normality of the resulting solution is
Assertion :Pure water obtained from different states of India always contains hydrogen and oxygen in the ratio of 1 : 8 by mass. Reason: Total mass of reactants and products during chemical change is always the same.
Assertion :Both 12g of carbon and 27g of aluminium contain 6.023 × 1023 atoms. Reason :Molar mass of an element contains Avogadro number of atoms.
Assertion: Equivalent weight of a base molecular weight = acidity Reason: Acidity is the number of replaceable hydrogen atom in one molecule of the base.
Assertion : Both 138 g of K₂CO₃ and 12 g of carbon have same number of carbon atoms. Reason : Both contains 1 g atom of carbon which contains 6.022 × 1023 carbon atoms.
Volume of acid that contains 63g pure acid is.
The total number of electrons present in 18 ml of water (density of water is 1 g ml–1) is
Assertion :Number of molecules present in SO₂ is twice the number of molecules present in O₂. Reason : Molecular mass of SO₂ is double to that of O₂.
A solution containing 12.0% NaOH by mass has a density of 1.131 g/mL. What volume of this solution contains 5.00 mol of NaOH ?
A solution of NaOH is prepared by dissolving 4.0 g of NaOH in 1 L of water. Calculate the volume of the HCl gas at STP that will neutralize 50 mL of this solution.
A 27.0 g sample of an unknown hydrocarbon was burned in excess O₂ to form 88g of CO₂ and 27g of H₂O. What is possible molecular formula of hydrocarbon ?
When a hydrate of Na₂CO₃ is heated until all the water is removed, it loses 54.3 per cent of its mass. The formula of the hydrate is
Volume of water required to make 1N solution from 2 mL conc. HNO₃.
If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will
In a compound C, H and N atoms are present as 9%, 1%, 3.5% respectively. Molecular weight of compound is 108. Molecular formula of compound is (a) C H N (b) C H N (c) C H N (d) C H N
Number of atoms in 560g of Fe (atomic mass 56 g mol–1) is
Calculate the analytical molarity of Cl– ion in solution which is prepared by mixing 100 ml of 0.1 M NaCl and 400 ml of 0.01 M BaCl₂.
The molarity of 68 % of H₂SO₄ whose density is 1.84 g/cc is
HCl is 80% ionised in 0.01 M aqueous solution. The equilibrium molarity of HCl in the solution is
The following process has been used to obtain iodine from oil-field brines in California. NaI + AgNO₃ → AgI + NaNO₃ AgI + Fe → FeI₂ + Ag FeI₂ + Cl₂ → FeCl₃ + I₂ If 381 kg of iodine is produced per hour then mass of A…
NX is produced by the following step of reactions M + X2 → M X2 MX2 + X2 → M3X8 M3X8 + N₂CO₃ → N X + CO₂ + M3O₄ How much M (metal) is consumed to produce 206 gm of NX. (Take At. wt of M = 56, N=23, X = 80)
100 mL of mixture of NaOH and Na₂SO₄ is neutralised by 10 mL of 0.5 M H₂SO₄. Hence, NaOH in 100 mL solution is
Assertion : If 30 mL of H₂ and 20 mL of O₂ react to form water, 5 mL of H₂ is left at the end of the reaction Reason :H₂ is the limiting reagent.
Assertion :For a binary solution of two liquids, A and B, with the knowledge of density of solution, molarity can be converted into molality. Reason: Molarity is defined in terms of volume and molality …
Assertion : 1mole of H₂SO₄ is neutralised by 2 moles of NaOH but 1 equivalent of H₂SO₄ is neutralised by 1 equivalent of NaOH. Reason : Equivalent weight of H₂SO₄ is half of its molecular weight while e…