19,000+ solved questions for JEE Advanced, JEE Mains, NEET & IChO — with answers and expert explanations.
N₂ + 3H₂ → 2NH₃ Molecular weight of NH₃ and N₂ are x1 and x2, respectively. Their equivalent weights are y1 and y2, respectively. Then (y1 – y2) is (a) 2x x
Given the reaction : Na O(s) H O( ) 2NaOH(aq) → l What is the molarity of the solution formed if 1.35g of Na₂O is mixed with H₂O such that the final volume is 100 mL?
A solution containing 12.0% NaOH by mass has a density of 1.131 g/mL. What volume of this solution contains 5.00 mol of NaOH ?
1 mole of oxalic acid is treated with conc. H₂SO₄. The resultant gaseous mixture is passed through a solution of KOH. The mass of KOH consumed will be (where KOH absorbs CO₂.) (COOH)₂ CO + CO₂ + H₂O 2 KOH + CO₂…
In a compound C, H and N atoms are present as 9%, 1%, 3.5% respectively. Molecular weight of compound is 108. Molecular formula of compound is (a) C H N (b) C H N (c) C H N (d) C H N
When a hydrate of Na₂CO₃ is heated until all the water is removed, it loses 54.3 per cent of its mass. The formula of the hydrate is
A 27.0 g sample of an unknown hydrocarbon was burned in excess O₂ to form 88g of CO₂ and 27g of H₂O. What is possible molecular formula of hydrocarbon ?
Number of atoms in 560g of Fe (atomic mass 56 g mol–1) is
If we consider that 1/6, in place of 1/12, mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will
P and Q are two elements which forms P₂Q3 and PQ2. If 0.15 mole of P₂Q3 weights 15.9g and 0.15 mole of PQ2 weights 9.3g, the atomic weight of P and Q is (respectively) :
100 mL of mixture of NaOH and Na₂SO₄ is neutralised by 10 mL of 0.5 M H₂SO₄. Hence, NaOH in 100 mL solution is
Assertion: Equivalent weight of a base molecular weight = acidity Reason: Acidity is the number of replaceable hydrogen atom in one molecule of the base.
Volume of acid that contains 63g pure acid is.
Assertion :Both 12g of carbon and 27g of aluminium contain 6.023 × 1023 atoms. Reason :Molar mass of an element contains Avogadro number of atoms.
Assertion :Pure water obtained from different states of India always contains hydrogen and oxygen in the ratio of 1 : 8 by mass. Reason: Total mass of reactants and products during chemical change is always the same.
The total number of electrons present in 18 ml of water (density of water is 1 g ml–1) is
A solution of NaOH is prepared by dissolving 4.0 g of NaOH in 1 L of water. Calculate the volume of the HCl gas at STP that will neutralize 50 mL of this solution.
Volume of water required to make 1N solution from 2 mL conc. HNO₃.
Normality of acid is.
HCl is 80% ionised in 0.01 M aqueous solution. The equilibrium molarity of HCl in the solution is
The molarity of 68 % of H₂SO₄ whose density is 1.84 g/cc is
Calculate the analytical molarity of Cl– ion in solution which is prepared by mixing 100 ml of 0.1 M NaCl and 400 ml of 0.01 M BaCl₂.
The following process has been used to obtain iodine from oil-field brines in California. NaI + AgNO₃ → AgI + NaNO₃ AgI + Fe → FeI₂ + Ag FeI₂ + Cl₂ → FeCl₃ + I₂ If 381 kg of iodine is produced per hour then mass of A…
Assertion : If 30 mL of H₂ and 20 mL of O₂ react to form water, 5 mL of H₂ is left at the end of the reaction Reason :H₂ is the limiting reagent.
Assertion :For a binary solution of two liquids, A and B, with the knowledge of density of solution, molarity can be converted into molality. Reason: Molarity is defined in terms of volume and molality …