19,000+ solved questions for JEE Advanced, JEE Mains, NEET & IChO — with answers and expert explanations.
At present, HNO₃ is industrially prepared by the
Oxygen is more electronegative than sulphur, yet H₂S is acidic in nature while H₂O is neutral because:
Ozone is an extremely powerful oxidizing agent. It is
At room temperature, O₃ is absorbed by
Volume of acid that contains 63g pure acid is.
Assertion: Equivalent weight of a base molecular weight = acidity Reason: Acidity is the number of replaceable hydrogen atom in one molecule of the base.
Assertion :Both 12g of carbon and 27g of aluminium contain 6.023 × 1023 atoms. Reason :Molar mass of an element contains Avogadro number of atoms.
Assertion :Pure water obtained from different states of India always contains hydrogen and oxygen in the ratio of 1 : 8 by mass. Reason: Total mass of reactants and products during chemical change is always the same.
A solution of NaOH is prepared by dissolving 4.0 g of NaOH in 1 L of water. Calculate the volume of the HCl gas at STP that will neutralize 50 mL of this solution.
The total number of electrons present in 18 ml of water (density of water is 1 g ml–1) is
In one molal solution that contains 0.5 mole of a solute, there is (NEET 2022)
The density of 2 M aqueous solution of NaOH is 1.28 g/cm3. The molality of the solution is [Given that molecular mass of NaOH = 40 g mol–1] (Odisha NEET 2019)
The number of moles of hydrogen molecules required to produce 20 moles of ammonia through Haber’s process is (NEET 2019)
Which of the following is dependent on temperature? (NEET 2017)
The number of water molecules is maximum in (NEET 2015)
If Avogadro number NA, is changed from 6.022 × 1023 mol–1 to 6.022 × 1020 mol–1, this would change (NEET 2015)
Which one of the following data has only four significant figures? (Kerala CEE 2014)
6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is (NEET 2013)
The vapour density of a gas is 11.2. The volume occupied by one gram of the gas at STP is (Manipal – 2013)
5.6 g of a metal forms 12.7 g of metal chloride. Hence equivalent weight of the metal is
0.115 g of pure sodium metal was dissolved in 400 ml distilled water. The normality of the above solution
The final molarity of a solution made by mixing 50 mL of 0.5 M HCl, 150mL of 0.25 M HCl and water to make the volume 250 mL is
Assertion (A) Molarity of a solution depends upon temperature. Reason (R) Volume of a solution is temperature dependent entity.
The molarity of a solution obtained by mixing 750 mL of 0.5 M HCl with 250 ml of 2 M HCl will be
In which mode of expression, the concentration of a solution remains independent of temperature ?