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shows Cannizzaro’s reaction due to
(a) (b) (c) (d)
Undergo Cannizaro reaction give product as (a) (b) (c) (d)
The reaction given is
The compound 푥is
Assertion(A) 2-butenal lacks enolisable H-atom, α to carbonyl group, still it has sufficient acidic character. Reason(R) The conjugate base of 2-butenal is stabilized by resonance. (AIIMS 2009)
The compound, with which ethanal does not react, is. (AFMC 2009)
The most reactive of the following is (J&K CET)
If heavy water is taken as solvent instead of normal water while performing Cannizzaro reaction, the products of the reaction are (AIIMS 2009)
Aldehydes and ketones are differentiated by using (UP CPMT 2010)
In the following reaction sequence, C H NH Cl Ca(OH) Alc.KOH CH CHO X Y -> -> Y is (MHT CET 2010)
Ethyl methyl ketone is obtained by heating calcium salts of (MHT CET 2010)
Identify the reaction which is used to obtain -hydroxy ketone? (Guj CET 2010)
Which of the following reaction will not result in the formation of carbon-carbon bonds? (CBSE AIPMT 2010)
Name the reagent used to bring about the following transformation : But-2-ene to ethanal (AMU 2010)
When ethanal is treated with Fehling’s solution, it gives a precipitate of (AFMC 2010)
The major product formed from the following reaction is (AFMC 2010) (a) (b) (c) (d)
An organic compound A burns with a sooty flame. It is negative towards Tollen’s reagent test and positive for Brady’s reagent test. The compound A is (KCET 2011)
Which of the following organic compounds answers both iodoform test Fehling’s test? (KCET 2013)
Ozonolysis (Reductive) X Y Z -> Y can be obtained by Etard’s reaction, Z undergoes disproportion reaction with concentrated alkali ,X could be (KCET 2014) (a) (b) (c) (d)
(i)CH MgBr (i)Dil.NaOH (ii) (ii)H O P R -> -> 4-methylpent-3-en-2-one compound P is (KCET 2014)
The correct statement regarding a carbonyl compound with a hydrogen atom on its alpha-carbon is (NEET 2016)
The IUPAC name of the compound (NEET 2017) is
Which of the following is paradehyde?
Ethanedial has which functional group ?