In the following redox equation, 2+ 2- + 2+ 3+ 2 7 xUO +Cr O +yH aUO +zCr +bH O -> the value of coefficients x, y and z respectively, are

It is a redox reaction that needs to be balanced 2+ 2- + 2+ +3 2 7 2 2 xUO +Cr O +yH aUO +zCr +bH O -> We write the reaction in two halves. Oxidation Half: 2+ 2+ 2 UO UO -> Reduction Half: 2- 3+ 2 7 Cr O 2Cr -> Then, the hydrogen and charge is balanced- 2- + - 3+ 2 7 2 Cr O +14H +6e 2Cr +7H O -> 2+ 2+ + - 2 2 UO +H O UO +2H +2e -> Thus, the balanced equation is- 2+ 2- + 2+ +3 2 7 2 2 3UO +Cr O +8H 3UO +2Cr +4H O -> Thus, the correct option is (a) x y z 3 8 2