MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Organic ChemistryPolymersPrevious Year Questions

Arrange the following in increasing order of their intermolecular forces: Nylon-6, 6 (I), Buna-S (II), Polythene (III) (AMU 2010)

A.II, I, III

B.III, II, I

C.I, II, III

D.II, III, I✓ Correct

Explanation

Nylon-6, 6 is a fibre and has hydrogen bonding as intermolecular force. Buna-S is an elastomer and has weak van der Waals’ forces. Polythene is thermoplastic and has intermediate intermolecular forces (i.e., stronger than elastomer but weaker than fibre). Thus, the increasing order of intermolecular forces is shown below: Buna-S (II) < polythene (III) < nylon-6, 6 (I)

Back to Question Bank

Practice More Like This

Take chapter-wise tests, track your progress, and master Polymers.

Start Free Practice →