MEDIUMMCQ SINGLEJEE Advanced ChemistryOrganic ChemistryPolymersPrevious Year Questions
Arrange the following in increasing order of their intermolecular forces: Nylon-6, 6 (I), Buna-S (II), Polythene (III) (AMU 2010)
A.II, I, III
B.III, II, I
C.I, II, III
D.II, III, I✓ Correct
Explanation
Nylon-6, 6 is a fibre and has hydrogen bonding as intermolecular force. Buna-S is an elastomer and has weak van der Waals’ forces. Polythene is thermoplastic and has intermediate intermolecular forces (i.e., stronger than elastomer but weaker than fibre). Thus, the increasing order of intermolecular forces is shown below: Buna-S (II) < polythene (III) < nylon-6, 6 (I)
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