The electronic configuration of Sodium (Na) and Chlorine (Cl) is 2 2 6 1 Na - 1s 2s 2p 3s It position in the third period and IA group 2 2 6 2 5 Cl - 1s 2s 2p 3s 3p It position in the third period and VIIA group Therefore, the correct option is d.
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