MEDIUMMCQ SINGLENEET ChemistryInorganic Chemistryp-Block (group 13 and 14)Previous Year Questions

It is because of inability of ns2 electrons of the valence shell to participate in bonding that (NEET 2017)

A.Sn2+ is oxidizing while Pb4+ is reducing.
B.Sn2+ and Pb2+ are both oxidizing and reducing.
C.Sn4+ is reducing while Pb4+ is oxidizing.
D.Sn2+ is reducing while Pb4+ is oxidizing.✓ Correct
Explanation

Inability of ns2 electrons of the valence shell to participate in bonding, on moving down the group in heavier p-block elements is called inert pair effect. Thus, Pb(II) is more stable that Pb(IV)and Sn(IV) is more stable than Sn(II). Therefore, Pb(IV) is easily reduced to Pb(II) and Sn(II) will be easily oxidised to Sn(IV). Thus, making Pb(IV) as oxidising agent and Sn(II) as reducing agent.

Practice More Like This

Take chapter-wise tests, track your progress, and master p-Block (group 13 and 14).

Start Free Practice →