HARDMCQ SINGLEJEE Advanced ChemistryInorganic Chemistryp-Block (group 13 and 14)Achiever Section
Compound (B) is:
A.NaBO2
B.Na2B4O7
C.Na3BO3✓ Correct
D.NaOH
Explanation
Fused 2 6 11 2 3 2 2 4 7 3 Ca B O Na CO NaBO Na B O CaCO + ¾¾¾® + + 2 2 2 4 7 2 3 NaBO CO Na B O Na CO + ® + 27. (C) Compound (C) is: (a) H2B4O7 (b) HBO2 (c) H3BO3 (d) HB3O5 p-BLOCK (GROUP 13 AND 14) 6 2 4 7 2 3 3 Na B O 2 HCl 5 H O 4 H BO acid C 2 NaCl B + + ® + 28. (C) Compound (D) is: (a) H3BO3 (b) B2O3 (c) B (d) none of these The reaction can be shown as- 2 6 11 2 3 3 2 4 7 2 2 4 7 2 3 4 3 3 3 3 2 3 3 2 2 2 2 Ca B O 2Na Co 2CaCo Na B O (B) 2NaBO Na B O 2 HCl 5 H O 4 H BO acid C 2 NaCl H BO (C) H O B OH H H BO HBO H O HBO B O (D) (A) B ( )- + D D + ® + + + + ® + + + ¾¾® + ¾¾® ƒ
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