The standard reduction potentials of the halogens are given below: - 0 2 - 0 2 - 0 2 - 0 2 F +2e 2F E = +2.87 V Cl +2e 2Cl E = +1.36 V Br +2e 2Br E = +1.08 V I +2e 2I E = +0.535 V -> -> -> -> The standard reduction potential value is directly proportional to the oxidizing power. Here, we can see that the value of standard reduction potential is highest for F2. So, F2 will have the highest oxidizing power. Hence, among the options, F2 is the most powerful oxidizing agent.
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