MEDIUMMCQ SINGLEJEE Advanced ChemistryInorganic Chemistryp -Block Elements (group 15-18)Previous Year Questions

Xenon hexafluoride reacts with silica to form a xenon compound X. The oxidation state of xenon in X is (JIPMER 2018)

A.+2

B.+4

C.+6✓ Correct

D.0

Explanation

Xenon hexafluoride reacts with silica to form XeOF4 as 2XeF6 + SiO2 -> 2XeOF4 + SiF4 The oxidation state of xenon in XeOF4 is + 6 as calculated below: Let the oxidation state of Xe is a. a + 1 x (–2) + 4 x (–1) = 0 a – 2 – 4 = 0 a = + 6

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