Molality of ethanol solution = 2 (given) i.e. 2 moles of ethanol is present in 1L i.e. 1000ml of solution. wt. of ethanol is solution= 2 46 92g x Wt. of solution = density × volume of solution 1.025 1000 1025g x Wt. of solvent = 1025 92 933g i.e. 0.933kg ∴ Moles of solute Molality Mass of solvent in Kg 2 2.14 0.933 The correct option is (b)
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