MEDIUMMCQ SINGLEJEE Advanced ChemistryPhysical ChemistryMole _ Equivalent ConceptPrevious Year Questions

What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction? CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l) [Calculate upto second place of decimal point] (NEET 2022)

A.1.25g
B.1.32g
C.3.65g
D.9.50g

Practice More Like This

Take chapter-wise tests, track your progress, and master Mole _ Equivalent Concept.

Start Free Practice →