Given, The equivalent weight of metal = 32 g MOLE & EQUIVALENT CONCEPT 54 Valency of the metal = 2 The atomic mass of given metal = Equivalent metal × Valency = 32 2 64g x The general formula of this metal nitrate is 3 2 M NO The molecular given metal nitrate = 6 4 2 14 3 16 6 4 2 62 1 88 g x Therefore, the molecular mass of a given bivalent metal nitrate is 188 grams.
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