MEDIUMMCQ SINGLEJEE Advanced ChemistryPhysical ChemistryMole _ Equivalent ConceptAtomic Theory
A sample of calcium carbonate (CaCO3) has the following percentage composition: Ca = 40%, C = 12%, O = 48%. If the law of constant proportions is true, then the weight of calcium in 4g of a sample of calcium carbonate obtained from another source will be:
A.0.016 g
B.0.16 g
C.1.6 g✓ Correct
D.16 g
Explanation
In 100g CaCO3, 40g Ca is present. In 4g CaCO3, Let x g Ca be present x 40 4 100 >> x = 1.6g