Millimoles of H+ produced = 20 x 0.05 = 1 Millimoles of OH- produced = 30 x 0.1 x 2 = 6 ( Each Ba (OH)2 gives 2OH-) Millimoles of OH- remaining in solution = 6 1 = 5 Total volume of solution = 20 + 30 = 50 mL 5 OH 0.1M 50
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