Find  out  the  solubility  of  Ni(OH)2  in  0.1  M  NaOH. Given that the ionic product of Ni(OH)2 is 2 10 x . (NEET 2020) (a) 2 10 M x (b) 2 10 M x (c) 1 10 M x (d) 1 10 M x

2+ 2 2 + 0.1M 0.1M 0.1M Ni OH Ni + 2OH s 2s s wheresis thesolubilityof Ni(OH) . NaOH Na + OH 2 2+ 2 2 15 15 13 OH = 2s +0.1=0.1 2s <<<0.1 Ionicproduct of Ni OH = Ni OH 2×10 =s 0.1 2×10 s = = 2×10 M 0.1×0.1