We know that, when equal concentration of acid and base are mixed, they get neutralized. But if the concentration of acid is greater than it is acidic. Similarly, if the concentration of base is greater than it is basic. Therefore, 1 1 2 2 M V M V =MV 0.1×1 0.01×1=M×2 M=0.09/2=0.045M Since, the molarity of NaOH is more, then the calculated pH is of alkaline nature. So the resulting pH can be found as- - [OH ]=0.045M pOH log(0.045) 1.35 pH 14 1.35 12.65 (basic). 35. Which one of the following pairs of solution is not an acidic buffer? (AIPMT 2
Take chapter-wise tests, track your progress, and master Ionic equilibrium.
Start Free Practice →