MEDIUMMCQ SINGLENEET ChemistryPhysical ChemistryIonic equilibriumSalt Hydrolysis

If the maximum concentration of PbCl2 in water is 0.01 M at 25ºC, its maximum concentration in 0.1 M NaCl will be

A.2 × 10–3 M

B.1× 10–4 M

C.1.6 × 10–2 M

D.4 × 10–4 M.✓ Correct

Explanation

The reaction can be written as- 2 2 PbCl Pb 2Cl The maximum concentration of lead ions= 0.01M Also, the concentration of chloride ions= 0.02M Now, the solubility product can be calculated as- 2 2 sp 2 6 sp K [Pb ][Cl ] K [0.01][0.02] 4.0 10 x On dissolving lead chloride in NaCl, we have chloride as common ion. Therefore, 2 2 2 2 sp 6 2 2 2 6 2 PbCl Pb 2Cl K [Pb ][Cl ] 4.0 10 [Pb ][0.1] [Pb ] 4.0 10 /[0.1] 0.0004 x x M

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