MEDIUMMCQ SINGLENEET ChemistryPhysical ChemistryIonic equilibriumSelf-ionization of Water
What is the pH of a 0.015 M Ba(OH)2 solution ?
A.1.82
B.1.52
C.12.48✓ Correct
D.12.18
Explanation
2 2 Ba OH Ba 2OH -> Thus, OH 0.015 2 0.03M x pOH = log OH 2 = log 3 10 x = 2 log3 1.52 And, pH + pOH = 14 pH = 14 – 1.52 = 12.48
Practice More Like This
Take chapter-wise tests, track your progress, and master Ionic equilibrium.
Start Free Practice →