Solubility of AgCl will be minimum in the solution which contains the highest concentration of the common ion Ag or Cl This eliminates option ‘b’ In option ‘a’ Ag = 0.001 M In option ‘d’ Cl = 0.01 M In option ‘c’ Cl = 0.01 2 x = 0.02 M Hence solubility of AgCl will be minimum in 0.01 M 2 CaCl solution.
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