MEDIUMMCQ SINGLEJEE Advanced ChemistryPhysical ChemistryIonic equilibriumConjugate Pair
Ka for HF is 3.5 × 10–4. Calculate Kb for the fluoride ion.
A.3.5 × 10–4
B.1.0 × 10–7
C.2.9 × 10–11✓ Correct
D.1.0 × 10–14
Explanation
HF and F are conjugate Acid-Base pair (CABP) for CABP, a b w K K = K x 14 11 w b 4 a K 10 K 2.86 10 K 3.5 10 x x IONIC EQUILIBRIUM 43 Salt Hydrolysis
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