From the given conditions, we know that- eqm. 2 2 4 4 eqm. + HCl H Cl 0.1 0 0 t =0 0 0.1 0.1 t H SO 2H SO 0.05 0 0 t =0 0 0.1 0.1 t [H ]will have same ionic concenteration. So, the pH value of 0.05 M sulphuric acid will be equal to 1.
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