If 11.1 mg of CaCl2 and 12 mg of MgSO4 are present in 2 L of water, what is its hardness (in gram CaCO3 / ppm)? (EAMCET 2008)

2 3 3 3 CaCl CaCO 40 35.5 2 40 12 48 111 10 mg 100 10 mg x x x 4 3 3 3 MgSO CaCO 24 35 64 40 12 48 120 10 mg 100 10 mg x x 3 111 10 x mg of CaCl2 = 3 100 10 x mg of CaCO3 11.1 mg of CaCl2 = 3 3 100 10 11.1 111 10 x x x mg of CaCO3 = 10 mg of CaCO3 Similarly, 3 120 10 x mg of MgSO4 = 3 100 10 x mg of CaCO3 12 mg of MgSO4 = 3 3 100 10 12 120 10 x x x mg of CaCO3 = 10 mg of CaCO3 In 2L of water, total weight of CaCO3 = 10 + 10 = 20 mg In 1L of water, total weight of CaCO3 = 20 mg 10mg 2 In 106 mg of water, total weight of CaCO3 = 10 mg So, in 106 part water, hardne