MEDIUMMCQ SINGLENEET ChemistryOrganic ChemistryHydrocarbonsIsomerism & Preparation of Alkynes

When CH CH CHCl is treated with NaNH2, the product formed is

A.CH3 – CH = CH2

B.CH3 – C≡CH✓ Correct

Explanation

Soda amide is a base which abstracts the acidic protons. 1,1-di-chloro propane on treatment with soda amide gives alkyne as the final product. H H3C Br Br H CH3 2NaNH3 H3C C CH3 C + HYDROCARBONS 15

Back to Question Bank

Practice More Like This

Take chapter-wise tests, track your progress, and master Hydrocarbons.

Start Free Practice →