MEDIUMMCQ SINGLEJEE Mains ChemistryOrganic ChemistryHydrocarbonsIsomerism & Preparation of Alkynes

When CH CH CHCl is treated with NaNH2, the product formed is

A.CH3 – CH = CH2

B.CH3 – C≡CH✓ Correct

Explanation

Soda amide is a base which abstracts the acidic protons. 1,1-di-chloro propane on treatment with soda amide gives alkyne as the final product. H H3C Br Br H CH3 2NaNH3 H3C C CH3 C + HYDROCARBONS 15

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