When 2-chloro-2-methylbutane is heated with alcoholic KOH, the possible product/s is/are (i) (CH3)2 C=CHCH3 (ii) CH2=C(CH3)CH2CH3 (iii) (CH3)2CHCH=CH2

The possible products obtained when 2-chloro-2-methylbutane with alcoholic KOH are 2-methyl but-2-ene and 2-methyl but-1-ene. Alcoholic KOH is a strong base and the chloro group is a good leaving group as shown- 3 2 3 3 ( )( ) KOH CH CH C CH Cl CH -> 2 3 2 3 3 3 3 ( ( ) ) CH C CH CH CH CH CH C CH CH