The addition of HBr to alkene takes place according to the Markovnikov rule. According to this effect, when an unsymmetrical alkene is treated with the unsymmetrical reagent, then the negative part of the reagent goes to the carbon-carbon double bond which has less number of hydrogen attached to it. 3 2 3 2 3 3 3 Br | H C CH CH=CH HBr CH C CH – CH | | CH CH -> Hence, the correct option is (d).
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