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MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryGaseous statePrevious Year Questions

The volume occupied by 1.8 g of water vapour at 374°C and 1 bar pressure will be [Use R = 0.083 bar L K-1 mol-1] (NEET (Odisha) 2019)

A.96.66 L
B.55.87 L✓ Correct
C.3.10 L
D.5.37 L
Explanation

According to ideal gas equation, pV = nRT or . nRT w RT V p M wt p ….(i) . w n M wt Given, w = 1.8 g, T = 374oC = (374 + 273) K = 674 K p = 1 bar, R = 0.083 bar L K-1 mol-1 On substituting the given values in Eq. (i) we get 1 1.8 18 g V g mol 1 1 0.083 bar LK mol 647 K 5.37 1 bar L x x 48. In an ideal gas equation which is constant? (JIPMER 2019) (a) Temperature (b) Pressure (c) Volume (d) Universal gas constant According to ideal gas equation, pV = nRT where, p = pressure, V = volume n = no. of moles, T = temperature R =

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