For the process: Cu2+ + 2e– → Cu; log[Cu2+] vs. Ered graph is shown in the figure, where OA = 0.3…

Question

For the process: Cu2+ + 2e– → Cu; log[Cu2+] vs. Ered graph is shown in the figure, where OA = 0.34 V. The electrode potential of the half-cell of Cu|Cu2+ (0.1 M) will be [2.303 RT/F = 0.06]

Accepted Answer

A. –0.31 V

For the process: Cu2+ + 2e– → Cu; log[Cu2+] vs. Ered graph is shown in the figure, where OA = 0.34 V. The electrode potential of the half-cell of Cu|Cu2+ (0.1 M) will be [2.303 RT/F = 0.06]

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