What is the correct order of spin only magnetic moment (in BM) of Mn2+, Cr2+ and Ti2+? (AFMC 2008)

The magnetic moment is calculated as, μ = n(n+2) Where n is the number of unpaired electrons and μ is the magnetic moment. 2+ Mn has 5 unpaired electrons. The magnetic moment of 2+ Mn is, μ = 5(5+2) = 5(7) 35 5.91 B.M. 2+ Cr has 4 unpaired electrons. The magnetic moment of 2+ Cr is, μ = 4(4+2) = 4(6) 24 4.89 B.M. 2+ Ti has 2 unpaired electrons. The magnetic moment of 2+ Ti is, μ = 2(2+2) = 2(4) 8 2.82 B.M. So, the correct order of spin only magnetic moment is 2+ 2+ 2+ Mn Cr i Thus, (c) is the correct option.