For a given ion, the magnetic moment is 2.83 BM. The total spin (s) of all the unpaired electrons is

The spin only magnetic moment can be calculated as: n n 2 , where n is the number of unpaired electrons. Given, 2.83 BM . Now, 2 2 2 2.83 2 2.83 2 8 2 2 8 0 Solving for n, 2 n n n n n n n n n >> >> >> It contains two unpaired e- D and F Block Elements 6 If spin is + 1 2 for one e- Then total spin its 1 2 1 2 x . 30. Among the following series of transition metal ions, the one in which all metal ions have 3d2, electronic configuration is (At. no. Ti = 22 ; V = 23 ; Cr = 24, Mn = 25) (a) Ti3+, V2+, Cr3+, Mn4+ b) Ti+, V4+, Cr6+, Mn7+ (c)