On treatment of 100 mL of 0.1 M solution of CoCl3.6H2O with excess of AgNO3; 1.2 × 1022 ions are precipitated. The complex is

The value of the avagadros number = 23 6.023×10 So, 22 1.2×10 ions will have = 22 23 1.2×10 =0.23moles 6.023×10 So, the 100 ml of the 0.1M solution of the given compound will have 100ml ×0.1M=0.01moles 1000ml/l So, the 0.01 moles of 3 2 CoCl .6H O reacts with the excess of 3 AgNO and form 0.02moles of AgCl precipitates this means that 0.01 moles of silver ions and 0.01 moles of the chloride ion. Thus, from the one mole of 3 2 CoCl .6H O there is displacement of one chlorine atom, Hence, the compound will be 2 5 2 2 [Co(H O) Cl]Cl .H O Hence, the correct answer is option (d)