Excess of silver nitrate solution is added to 100 mL of 0.01 M pentaaquachlorochromium (III) chloride solution. The mass of silver chloride obtained (in gram) is [Atomic mass of silver is 108]

2 5 2 Cr(H O) Cl Cl is used as a reagent. This states that - 2Cl can be combined with Ag to give AgCl. No of moles of - Cl = 2×100×0.01=0.002 1000 Therefore, moles of AgCl ppt will be 0.002 Hence, its mass will be = 0.002×143.5=287×10–3g. Hence, the correct option is (a)