In the complex with formula MCl3. 4H2O, the coordination number of the metal M is six and there is no molecule of hydration in it. The volume, if 0.1 M AgNO3 solution needed to precipitate the free chloride ions in 200 mL of 0.01 M solution of the complex, is

The coordination number of metal = 6 The number of molecules of hydration=0 Thus, the formula of the complex =[M(H2O)4Cl2]Cl The complex has free chloride ion concentration of 0.01M. - - 3 3 1 1 2 2 1 2 2 2 1Cl +1AgNO AgCl+NO M V M V = n n 0.1×V 0.01×200 = 1 1 V =20mL -> Hence, option (b) is the correct answer.