An excess of AgNO3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be (NEET 2013)

3 excess AgNO 2 2 4 2 4 2 Cr H O Cl Cl Cr H O Cl AgCl -> Using formula, No. of moles Molarity= ×1000 volume No. of moles 0.01= ×1000 100 No. of moles of AgCl = 0.001 Hence, the correct option is (a).