In 4 Ni(CO) the oxidation state of Ni is 0 and Co is a strong field ligand, the hybridization will be 3 sp and shape will be tetrahedral. In 3 2 2 Ni(PPh ) Cl the oxidation state of Ni is +2 and Cl is a weak field ligand Hence, the hybridization will be 3 sp and shape will be tetrahedral. Hence, the correct answer is option (c)
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