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HARDMCQ SINGLEJEE Advanced ChemistryInorganic ChemistryCoordination compoundsAchiever Section

Which one of the following has largest number of isomers? (R = alkyl group, en = ethylenediamine)

A.[Ru(NH3)4 Cl2]+
B.[Co (NH3)5 Cl]2+
C.K4[Fe(CN)6]
D.[Co (en)2 Cl2]+✓ Correct
Explanation

[Co (en)2 Cl2]+ has the largest number of isomers among the following. This includes the geometrical isomers i.e. cis and trans isomers and the stereoisomers which includes the d form, l form and the optically inactive molecules. [Ru(NH3)4 Cl2]+ has two geometrical isomers cis and trans. [Co(NH3)5Cl]2+ has no isomers. [Ir(PR3)2H(CO)]2+ has two geometrical isomers cis and trans. Hence, the correct answer is option (d).

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