To calculate the oxidation state first let‘s assume the oxidation state of Cr to be x 2 6 3 6 6 2 2 2 2 2 3 1.[Cr(H O) ]Cl x+6×0+3×(-1)=0 x=+3 2.[Cr(C H ) ] x+2×0=0 x=0 3.K [Cr(CN) (O) (O )(NH ) 2×(+1)+x+2×(-1)+(-2)×2-2+0=0 x=+6 Hence, the correct answer is option (d) Ligand
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