The rate constant of a reaction is given by ln k (sec–1) = 14.34 – (1.25 × 104)/T What will be the energy of activation?

Comparing given form with Arrhenius equation, 1 ln ln x a E k A R T We can get, 4 1.25 10 a E R x 4 4 1.25 10 1.25 10 2 cal 1.987 2calk/mole 25 cal/mole >> x x x x a E R R k