The rate law for inversion of cane sugar is R=k [C12H22O11][H2O]. Find the concentration of sucrose if the rate of the reaction is 0.032 s-1 and rate constant k=0.005.

Given, rate constant k=0.005, rate of the reaction R=0.032 s-1. Inversion of cane sugar is a pseudo first order reaction and water is present in large excess so the rate law becomes R=k [C12H22O11] 0.032= 0.005 [C12H22O11] [C12H22O11]=6.4 M.