If half-life of a substance is 36 minutes. Find amount left after 2 hrs. Initial amount is 10 g. (JIPMER 2019)

Given, t1/2 = 36 min t = 2hrs = 120 min, 0 10 A g For first order reaction, 1/2 0.693 k t 0.693 k 0.01925 36 o A 2.303 t log g k A Where, 0 A = initial amount = 10 g A final amount 2.303 10 120 log 0.01925 A log10 log A 1 1 log A 1 log A 0 A 1g