2 2 3 eq N 3H 2NH t 0 a 3a 0 t t a(1 ) 3a(1 ) 2a Given 50% reacted 1 2 3 NH P = (mole fraction) x (total pressure) 3 NH 1 2 × ×P P 2 P = = 1 3 α× 4 - 2× 2
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