Dissociation of 33 percent means that out of one mole of AB, moles dissociated are 1/3. So, the number of moles present = 1 2 1 3 3 AB(g) A(g)+B(g) T 0 1 0 0 2 1 1 Equilibrium 3 3 3 Number of moles after dissociation 2 1 1 4 + + = 3 3 3 3 The partial pressures for A and B are A B A B p AB p p 1/3 P P = P = ×P= 4/3 4 P P × P P 4 4 K = = P P 2 P K = 8 P=8K Hence, the correct answer is option (d)
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