1.1 mole of A is mixed with 2.2 mole of B and the mixture is kept in a one-litre flask till the equilibrium, A + 2B 2C + D is reached. At equilibrium 0.2 mol of C is formed. The equilibrium constant of the above reaction is

A+2B 2C+D a b 0 0 Initial ( ) a x ( 2 ) b x 2x x At equilibrium the value of equilibrium constant 2 c 2 3 c 2 [C] [D] K [A][B] 4x K (a x)(b 2x) nc = 0.2 2x = 0.2 x = 0.1 3 c 2 4(0.1) K 0.001 (1.1 0.1)(2.2 0.2) Hence, the correct answer is option (c)