In the reaction, H2 + I2 2HI. In a 2 litre flask 0.4 moles of each H2 and I2 are taken. At equilibrium 0.5 moles of HI are formed. What will be the value of equilibrium constant, Kc
A.20.2
C.0.284
D.11.1✓ Correct
Explanation
2 2 H I 2HI Initial 0.4 0.4 0 At Equil 0.4 0.25 0.4 0.25 0.5 2 2 C 2 2 HI (0.5 ) K = = = 11.1 H I 0.15×0.15