MEDIUMMCQ SINGLEJEE Mains ChemistryPhysical ChemistryChemical EquilibriumPrevious Year Questions
The dissociation equilibrium of a gas AB can be represented as 2AB (g) 2AB(g) B (g) The degree of dissociation is ‘x’ and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant p K and total pressure p is (CBSE AIPMT 2008) (a) p 2K p (b) 1/3 p 2K p (c) 1/ 2 p 2K p (d) p K p
Answer
B
Explanation
2 2 2AB (g) 2AB(g) B (g) p 0 0 p(1 ) p 0.5 p Hence, the equilibrium constant, 2 2 2 AB B p 2 AB 2 p 2 3 p 2 3 p P ×P K = P (αp) ×(0.5αp) K = [p(1-α)] 0.5α K = p (1-α) K = p×0.5α ...(1) Since, the degree of dissociation is small compared to
Practice More Like This
Take chapter-wise tests, track your progress, and master Chemical Equilibrium.
Start Free Practice →