A + B C + D. If finally the concentration of A and B are both equal but at equilibrium concentration of D will be twice of that of A then what will be the equilibrium constant of reaction.
A.4 / 9
B.9 / 4
C.1 / 9
D.4✓ Correct
Explanation
A = B and C D =2 A So, C [C][D] K [A][B] 2[A]2[A] [A][A] KC = 4